The Art of
ASSEMBLY LANGUAGE PROGRAMMING

Chapter Eighteen (Part 4)

Table of Content

Chapter Eighteen (Part 6)

CHAPTER EIGHTEEN:
RESIDENT PROGRAMS (Part 5)
18.8 - A Keyboard Monitor TSR
18.8 A Keyboard Monitor TSR

The following program extends the keystroke counter program presented a little earlier in this chapter. This particular program monitors keystrokes and each minute writes out data to a file listing the date time and approximate number of keystrokes in the last minute.

This program can help you discover how much time you spend typing versus thinking at a display screen.

; This is an example of an active TSR that counts keyboard interrupts
; once activated. Every minute it writes the number of keyboard
; interrupts that occurred in the previous minute to an output file.
; This continues until the user removes the program from memory.
;
;
; Usage:
;       KEYEVAL filename-       Begins logging keystroke data to
;                               this file.
;
;       KEYEVAL REMOVE  -       Removes the resident program from
;                               memory.
;
;
; This TSR checks to make sure there isn't a copy already active in
; memory. When doing disk I/O from the interrupts
it checks to make
; sure DOS isn't busy and it preserves application globals (PSP
DTA

; and extended error info). When removing itself from memory
it
; makes sure there are no other interrupts chained into any of its
; interrupts before doing the remove.
;
; The resident segment definitions must come before everything else.

ResidentSeg     segment para public 'Resident'
ResidentSeg     ends

EndResident     segment para public 'EndRes'
EndResident     ends

.xlist
.286
include         stdlib.a
includelib      stdlib.lib
.list


; Resident segment that holds the TSR code:

ResidentSeg     segment para public 'Resident'
assume  cs:ResidentSeg
ds:nothing

; Int 2Fh ID number for this TSR:

MyTSRID         byte    0

; The following variable counts the number of keyboard interrupts

KeyIntCnt       word    0

; Counter counts off the number of milliseconds that pass
SecCounter
; counts off the number of seconds (up to 60).

Counter         word    0
SecCounter      word    0

; FileHandle is the handle for the log file:

FileHandle      word    0

; NeedIO determines if we have a pending I/O opearation.

NeedIO          word    0

; PSP is the psp address for this program.

PSP             word    0

; Variables to tell us if DOS
INT 13h
or INT 16h are busy:

InInt13         byte    0
InInt16         byte    0
InDOSFlag       dword   ?

; These variables contain the original values in the interrupt vectors
; we've patched.

OldInt9         dword   ?
OldInt13        dword   ?
OldInt16        dword   ?
OldInt1C        dword   ?
OldInt28        dword   ?
OldInt2F        dword   ?


; DOS data structures:

ExtErr          struct
eeAX            word    ?
eeBX            word    ?
eeCX            word    ?
eeDX            word    ?
eeSI            word    ?
eeDI            word    ?
eeDS            word    ?
eeES            word    ?
word    3 dup (0)
ExtErr          ends



XErr            ExtErr  {}      ;Extended Error Status.
AppPSP          word    ?       ;Application PSP value.
AppDTA          dword   ?       ;Application DTA address.


; The following data is the output record. After storing this data
; to these variables
the TSR writes this data to disk.

month           byte    0
day             byte    0
year            word    0
hour            byte    0
minute          byte    0
second          byte    0
Keystrokes      word    0
RecSize         =       $-month







; MyInt9-       The system calls this routine every time a keyboard
;               interrupt occus. This routine increments the
;               KeyIntCnt variable and then passes control on to the
;               original Int9 handler.

MyInt9          proc    far
inc     ResidentSeg:KeyIntCnt
jmp     ResidentSeg:OldInt9
MyInt9          endp





; MyInt1C-      Timer interrupt. This guy counts off 60 seconds and then
;               attempts to write a record to the output file. Of course

;               this call has to jump through all sorts of hoops to keep
;               from reentering DOS and other problematic code.

MyInt1C         proc    far
assume  ds:ResidentSeg

push    ds
push    es
pusha                           ;Save all the registers.
mov     ax
ResidentSeg
mov     ds
ax

pushf
call    OldInt1C

; First things first
let's bump our interrupt counter so we can count
; off a minute. Since we're getting interrupted about every 54.92549
; milliseconds
let's shoot for a little more accuracy than 18 times
; per second so the timings don't drift too much.

add     Counter
549            ;54.9 msec per int 1C.
cmp     Counter
10000          ;1 second.
jb      NotSecYet
sub     Counter
10000
inc     SecCounter
NotSecYet:


; If NEEDIO is not zero
then there is an I/O operation in progress.
; Do not disturb the output values if this is the case.

cli                     ;This is a critical region.
cmp     NeedIO
0
jne     SkipSetNIO

; Okay
no I/O in progress
see if a minute has passed since the last
; time we logged the keystrokes to the file. If so
it's time to start
; another I/O operation.

cmp     SecCounter
60  ;One minute passed yet?
jb      Int1CDone
mov     NeedIO
1       ;Flag need for I/O.
mov     ax
KeyIntCnt   ;Copy this to the output
shr     ax
1           ; buffer after computing
mov     KeyStrokes
ax  ; # of keystrokes.
mov     KeyIntCnt
0    ;Reset for next minute.
mov     SecCounter
0

SkipSetNIO:     cmp     NeedIO
1       ;Is the I/O already in
jne     Int1CDone       ; progress? Or done?

call    ChkDOSStatus    ;See if DOS/BIOS are free.
jnc     Int1CDone       ;Branch if busy.

call    DoIO            ;Do I/O if DOS is free.

Int1CDone:      popa                    ;Restore registers and quit.
pop     es
pop     ds
iret
MyInt1C         endp
assume  ds:nothing


; MyInt28-              Idle interrupt. If DOS is in a busy-wait loop waiting for
;               I/O to complete
it executes an int 28h instruction each
;               time through the loop. We can ignore the InDOS and CritErr
;               flags at that time
and do the I/O if the other interrupts
;               are free.

MyInt28         proc    far
assume  ds:ResidentSeg

push    ds
push    es
pusha                   ;Save all the registers.
mov     ax
ResidentSeg
mov     ds
ax

pushf                   ;Call the next INT 28h
call    OldInt28        ; ISR in the chain.

cmp     NeedIO
1       ;Do we have a pending I/O?
jne     Int28Done

mov     al
InInt13     ;See if BIOS is busy.
or      al
InInt16
jne     Int28Done

call    DoIO            ;Go do I/O if BIOS is free.

Int28Done:      popa
pop     es
pop     ds
iret
MyInt28         endp
assume  ds:nothing


; MyInt16-      This is just a wrapper for the INT 16h (keyboard trap)
;               handler.

MyInt16         proc    far
inc     ResidentSeg:InInt16

; Call original handler:

pushf
call    ResidentSeg:OldInt16

; For INT 16h we need to return the flags that come from the previous call.

pushf
dec     ResidentSeg:InInt16
popf
retf    2               ;Fake IRET to keep flags.
MyInt16         endp


; MyInt13-      This is just a wrapper for the INT 13h (disk I/O trap)
;               handler.

MyInt13         proc    far
inc     ResidentSeg:InInt13
pushf
call    ResidentSeg:OldInt13
pushf
dec     ResidentSeg:InInt13
popf
retf    2               ;Fake iret to keep flags.
MyInt13         endp


; ChkDOSStatus- Returns with the carry clear if DOS or a BIOS routine
;               is busy and we can't interrupt them.

ChkDOSStatus    proc    near
assume  ds:ResidentSeg
les     bx
InDOSFlag
mov     al
es:[bx]     ;Get InDOS flag.
or      al
es:[bx-1]   ;OR with CritErr flag.
or      al
InInt16     ;OR with our wrapper
or      al
InInt13     ; values.
je      Okay2Call
clc
ret

Okay2Call:      clc
ret
ChkDOSStatus    endp
assume  ds:nothing


; PreserveDOS-  Gets a copy's of DOS' current PSP
DTA
and extended
;               error information and saves this stuff. Then it sets
;               the PSP to our local PSP and the DTA to PSP:80h.

PreserveDOS     proc    near
assume  ds:ResidentSeg

mov     ah
51h         ;Get app's PSP.
int     21h
mov     AppPSP
bx      ;Save for later

mov     ah
2Fh         ;Get app's DTA.
int     21h
mov     word ptr AppDTA
bx
mov     word ptr AppDTA+2
es

push    ds
mov     ah
59h         ;Get extended err info.
xor     bx
bx
int     21h

mov     cs:XErr.eeDS
ds
pop     ds
mov     XErr.eeAX
ax
mov     XErr.eeBX
bx
mov     XErr.eeCX
cx
mov     XErr.eeDX
dx
mov     XErr.eeSI
si
mov     XErr.eeDI
di
mov     XErr.eeES
es

; Okay
point DOS's pointers at us:

mov     bx
PSP
mov     ah
50h         ;Set PSP.
int     21h

push    ds              ;Set the DTA to
mov     ds
PSP         ; address PSP:80h
mov     dx
80h
mov     ah
1Ah         ;Set DTA call.
int     21h
pop     ds

ret
PreserveDOS     endp
assume  ds:nothing



; RestoreDOS-   Restores DOS' important global data values back to the
;               application's values.

RestoreDOS      proc    near
assume  ds:ResidentSeg

mov     bx
AppPSP
mov     ah
50h                 ;Set PSP
int     21h

push    ds
lds     dx
AppDTA
mov     ah
1Ah                 ;Set DTA
int     21h
pop     ds
push    ds

mov     si
offset XErr         ;Saved extended error stuff.
mov     ax
5D0Ah               ;Restore XErr call.
int     21h
pop     ds
ret
RestoreDOS      endp
assume  ds:nothing


; DoIO-         This routine processes each of the I/O operations
;               required to write data to the file.

DoIO            proc    near
assume  ds:ResidentSeg

mov     NeedIO
0FFh            ;A busy flag for us.

; The following Get Date DOS call may take a while
so turn the
; interrupts back on (we're clear of the critical section once we
; write 0FFh to NeedIO).

sti
call    PreserveDOS             ;Save DOS data.

mov     ah
2Ah                 ;Get Date DOS call
int     21h
mov     month
dh
mov     day
dl
mov     year
cx

mov     ah
2Ch                 ;Get Time DOS call
int     21h
mov     hour
ch
mov     minute
cl
mov     second
dh

mov     ah
40h                 ;DOS Write call
mov     bx
FileHandle          ;Write data to this file.
mov     cx
RecSize             ;This many bytes.
mov     dx
offset month        ;Starting at this address.
int     21h                     ;Ignore return errors (!).
mov     ah
68h                 ;DOS Commit call
mov     bx
FileHandle          ;Write data to this file.
int     21h                     ;Ignore return errors (!).

mov     NeedIO
0               ;Ready to start over.
call    RestoreDOS

PhasesDone:             ret
DoIO            endp
assume  ds:nothing



; MyInt2F-      Provides int 2Fh (multiplex interrupt) support for this
;               TSR. The multiplex interrupt recognizes the following
;               subfunctions (passed in AL):
;
;               00- Verify presence.    Returns 0FFh in AL and a pointer
;                                       to an ID string in es:di if the
;                                       TSR ID (in AH) matches this
;                                       particular TSR.
;
;               01- Remove.             Removes the TSR from memory.
;                                       Returns 0 in AL if successful

;                                       1 in AL if failure.

MyInt2F         proc    far
assume  ds:nothing

cmp     ah
MyTSRID     ;Match our TSR identifier?
je      YepItsOurs
jmp     OldInt2F

; Okay
we know this is our ID
now check for a verify vs. remove call.

YepItsOurs:     cmp     al
0           ;Verify Call
jne     TryRmv
mov     al
0ffh        ;Return success.
lesi    IDString
iret                    ;Return back to caller.

IDString        byte    "Keypress Logger TSR"
0

TryRmv:         cmp     al
1           ;Remove call.
jne     IllegalOp

call    TstRmvable      ;See if we can remove this guy.
je      CanRemove       ;Branch if we can.
mov     ax
1           ;Return failure for now.
iret

; Okay
they want to remove this guy *and* we can remove it from memory.
; Take care of all that here.

assume  ds:ResidentSeg

CanRemove:      push    ds
push    es
pusha
cli                     ;Turn off the interrupts while
mov     ax
0           ; we mess with the interrupt
mov     es
ax          ; vectors.
mov     ax
cs
mov     ds
ax

mov     ax
word ptr OldInt9
mov     es:[9*4]
ax
mov     ax
word ptr OldInt9+2
mov     es:[9*4 + 2]
ax

mov     ax
word ptr OldInt13
mov     es:[13h*4]
ax
mov     ax
word ptr OldInt13+2
mov     es:[13h*4 + 2]
ax

mov     ax
word ptr OldInt16
mov     es:[16h*4]
ax
mov     ax
word ptr OldInt16+2
mov     es:[16h*4 + 2]
ax

mov     ax
word ptr OldInt1C
mov     es:[1Ch*4]
ax
mov     ax
word ptr OldInt1C+2
mov     es:[1Ch*4 + 2]
ax

mov     ax
word ptr OldInt28
mov     es:[28h*4]
ax
mov     ax
word ptr OldInt28+2
mov     es:[28h*4 + 2]
ax

mov     ax
word ptr OldInt2F
mov     es:[2Fh*4]
ax
mov     ax
word ptr OldInt2F+2
mov     es:[2Fh*4 + 2]
ax


; Okay
with that out of the way
let's close the file.
; Note: INT 2F shouldn't have to deal with DOS busy because it's
; a passive TSR call.

mov     ah
3Eh         ;Close file command
mov     bx
FileHandle
int     21h

; Okay
one last thing before we quit- Let's give the memory allocated
; to this TSR back to DOS.

mov     ds
PSP
mov     es
ds:[2Ch]    ;Ptr to environment block.
mov     ah
49h         ;DOS release memory call.
int     21h

mov     ax
ds          ;Release program code space.
mov     es
ax
mov     ah
49h
int     21h

popa
pop     es
pop     ds
mov     ax
0           ;Return Success.
iret


; They called us with an illegal subfunction value. Try to do as little
; damage as possible.

IllegalOp:      mov     ax
0           ;Who knows what they were thinking?
iret
MyInt2F         endp
assume  ds:nothing





; TstRmvable-           Checks to see if we can remove this TSR from memory.
;               Returns the zero flag set if we can remove it
clear
;               otherwise.

TstRmvable      proc    near
cli
push    ds
mov     ax
0
mov     ds
ax

cmp     word ptr ds:[9*4]
offset MyInt9
jne     TRDone
cmp     word ptr ds:[9*4 + 2]
seg MyInt9
jne     TRDone

cmp     word ptr ds:[13h*4]
offset MyInt13
jne     TRDone
cmp     word ptr ds:[13h*4 + 2]
seg MyInt13
jne     TRDone

cmp     word ptr ds:[16h*4]
offset MyInt16
jne     TRDone
cmp     word ptr ds:[16h*4 + 2]
seg MyInt16
jne     TRDone

cmp     word ptr ds:[1Ch*4]
offset MyInt1C
jne     TRDone
cmp     word ptr ds:[1Ch*4 + 2]
seg MyInt1C
jne     TRDone

cmp     word ptr ds:[28h*4]
offset MyInt28
jne     TRDone
cmp     word ptr ds:[28h*4 + 2]
seg MyInt28
jne     TRDone

cmp     word ptr ds:[2Fh*4]
offset MyInt2F
jne     TRDone
cmp     word ptr ds:[2Fh*4 + 2]
seg MyInt2F
TRDone:         pop     ds
sti
ret
TstRmvable      endp
ResidentSeg     ends



cseg            segment para public 'code'
assume  cs:cseg
ds:ResidentSeg

; SeeIfPresent- Checks to see if our TSR is already present in memory.
;               Sets the zero flag if it is
clears the zero flag if
;               it is not.

SeeIfPresent    proc    near
push    es
push    ds
push    di
mov     cx
0ffh        ;Start with ID 0FFh.
IDLoop:         mov     ah
cl
push    cx
mov     al
0           ;Verify presence call.
int     2Fh
pop     cx
cmp     al
0           ;Present in memory?
je      TryNext
strcmpl
byte    "Keypress Logger TSR"
0
je      Success

TryNext:        dec     cl              ;Test USER IDs of 80h..FFh
js      IDLoop
cmp     cx
0           ;Clear zero flag.
Success:                pop     di
pop     ds
pop     es
ret
SeeIfPresent    endp



; FindID-       Determines the first (well
last actually) TSR ID available
;               in the multiplex interrupt chain. Returns this value in
;               the CL register.
;
;               Returns the zero flag set if it locates an empty slot.
;               Returns the zero flag clear if failure.

FindID          proc    near
push    es
push    ds
push    di

mov     cx
0ffh        ;Start with ID 0FFh.
IDLoop:         mov     ah
cl
push    cx
mov     al
0           ;Verify presence call.
int     2Fh
pop     cx
cmp     al
0           ;Present in memory?
je      Success
dec     cl              ;Test USER IDs of 80h..FFh
js      IDLoop
xor     cx
cx
cmp     cx
1           ;Clear zero flag
Success:                pop     di
pop     ds
pop     es
ret
FindID          endp



Main            proc
meminit

mov     ax
ResidentSeg
mov     ds
ax

mov     ah
62h         ;Get this program's PSP
int     21h             ; value.
mov     PSP
bx

; Before we do anything else
we need to check the command line
; parameters. We must have either a valid filename or the
; command "remove". If remove appears on the command line
then remove
; the resident copy from memory using the multiplex (2Fh) interrupt.
; If remove is not on the command line
we'd better have a filename and
; there had better not be a copy already loaded into memory.

argc
cmp     cx
1           ;Must have exactly 1 parm.
je      GoodParmCnt
print
byte    "Usage:"
cr
lf
byte    " KeyEval filename"
cr
lf
byte    "or KeyEval REMOVE"
cr
lf
0
ExitPgm


; Check for the REMOVE command.

GoodParmCnt:    mov     ax
1
argv
stricmpl
byte    "REMOVE"
0
jne     TstPresent

call    SeeIfPresent
je      RemoveIt
print
byte    "TSR is not present in memory
cannot remove"
byte    cr
lf
0
ExitPgm

RemoveIt:       mov     MyTSRID
cl
printf
byte    "Removing TSR (ID #%d) from memory..."
0
dword   MyTSRID

mov     ah
cl
mov     al
1           ;Remove cmd
ah contains ID
int     2Fh
cmp     al
1           ;Succeed?
je      RmvFailure
print
byte    "removed."
cr
lf
0
ExitPgm

RmvFailure:             print
byte    cr
lf
byte    "Could not remove TSR from memory."
cr
lf
byte    "Try removing other TSRs in the reverse order "
byte    "you installed them."
cr
lf
0
ExitPgm



; Okay
see if the TSR is already in memory. If so
abort the
; installation process.

TstPresent:     call    SeeIfPresent
jne     GetTSRID
print
byte    "TSR is already present in memory."
cr
lf
byte    "Aborting installation process"
cr
lf
0
ExitPgm


; Get an ID for our TSR and save it away.

GetTSRID:       call    FindID
je      GetFileName
print
byte    "Too many resident TSRs
cannot install"
cr
lf
0
ExitPgm


; Things look cool so far
check the filename and open the file.

GetFileName:    mov     MyTSRID
cl
printf
byte    "Keypress logger TSR program"
cr
lf
byte    "TSR ID = %d"
cr
lf
byte    "Processing file:"
0
dword   MyTSRID

puts
putcr

mov     ah
3Ch         ;Create file command.
mov     cx
0           ;Normal file.
push    ds
push    es              ;Point ds:dx at name
pop     ds
mov     dx
di
int     21h             ;Open the file
jnc     GoodOpen
print
byte    "DOS error #"
0
puti
print
byte    " opening file."
cr
lf
0
ExitPgm

GoodOpen:       pop     ds
mov     FileHandle
ax  ;Save file handle.


InstallInts:            print
byte    "Installing interrupts..."
0


; Patch into the INT 9
13h
16h
1Ch
28h
and 2Fh interrupt vectors.
; Note that the statements above have made ResidentSeg the current data
; segment
so we can store the old values directly into
; the OldIntxx variables.

cli                     ;Turn off interrupts!
mov     ax
0
mov     es
ax
mov     ax
es:[9*4]
mov     word ptr OldInt9
ax
mov     ax
es:[9*4 + 2]
mov     word ptr OldInt9+2
ax
mov     es:[9*4]
offset MyInt9
mov     es:[9*4+2]
seg ResidentSeg

mov     ax
es:[13h*4]
mov     word ptr OldInt13
ax
mov     ax
es:[13h*4 + 2]
mov     word ptr OldInt13+2
ax
mov     es:[13h*4]
offset MyInt13
mov     es:[13h*4+2]
seg ResidentSeg

mov     ax
es:[16h*4]
mov     word ptr OldInt16
ax
mov     ax
es:[16h*4 + 2]
mov     word ptr OldInt16+2
ax
mov     es:[16h*4]
offset MyInt16
mov     es:[16h*4+2]
seg ResidentSeg

mov     ax
es:[1Ch*4]
mov     word ptr OldInt1C
ax
mov     ax
es:[1Ch*4 + 2]
mov     word ptr OldInt1C+2
ax
mov     es:[1Ch*4]
offset MyInt1C
mov     es:[1Ch*4+2]
seg ResidentSeg

mov     ax
es:[28h*4]
mov     word ptr OldInt28
ax
mov     ax
es:[28h*4 + 2]
mov     word ptr OldInt28+2
ax
mov     es:[28h*4]
offset MyInt28
mov     es:[28h*4+2]
seg ResidentSeg

mov     ax
es:[2Fh*4]
mov     word ptr OldInt2F
ax
mov     ax
es:[2Fh*4 + 2]
mov     word ptr OldInt2F+2
ax
mov     es:[2Fh*4]
offset MyInt2F
mov     es:[2Fh*4+2]
seg ResidentSeg
sti                     Okay
ints back on.

; We're hooked up
the only thing that remains is to terminate and
; stay resident.

print
byte    "Installed."
cr
lf
0


mov     dx
EndResident ;Compute size of program.
sub     dx
PSP
mov     ax
3100h       ;DOS TSR command.
int     21h
Main            endp
cseg            ends

sseg            segment para stack 'stack'
stk             db      1024 dup ("stack ")
sseg            ends

zzzzzzseg       segment para public 'zzzzzz'
LastBytes       db      16 dup (?)
zzzzzzseg       ends
end     Main

The following is a short little application that reads the data file produced by the above program and produces a simple report of the date time and keystrokes:

; This program reads the file created by the KEYEVAL.EXE TSR program.
; It displays the log containing dates
times
and number of keystrokes.

.xlist
.286
include         stdlib.a
includelib      stdlib.lib
.list

dseg            segment para public 'data'

FileHandle      word    ?

month           byte    0
day             byte    0
year            word    0
hour            byte    0
minute          byte    0
second          byte    0
KeyStrokes      word    0
RecSize         =       $-month

dseg            ends




cseg            segment para public 'code'
assume  cs:cseg
ds:dseg

; SeeIfPresent- Checks to see if our TSR is present in memory.
;               Sets the zero flag if it is
clears the zero flag if
;               it is not.

SeeIfPresent    proc    near
push    es
push    ds
pusha
mov     cx
0ffh                ;Start with ID 0FFh.
IDLoop:         mov     ah
cl
push    cx
mov     al
0           ;Verify presence call.
int     2Fh
pop     cx
cmp     al
0           ;Present in memory?
je      TryNext
strcmpl
byte    "Keypress Logger TSR"
0
je      Success

TryNext:        dec     cl              ;Test USER IDs of 80h..FFh
js      IDLoop
cmp     cx
0           ;Clear zero flag.
Success:                popa
pop     ds
pop     es
ret
SeeIfPresent    endp



Main            proc
meminit

mov     ax
dseg
mov     ds
ax



argc
cmp     cx
1           ;Must have exactly 1 parm.
je      GoodParmCnt
print
byte    "Usage:"
cr
lf
byte    " KEYRPT filename"
cr
lf
0
ExitPgm



GoodParmCnt:    mov     ax
1
argv

print
byte    "Keypress logger report program"
cr
lf
byte    "Processing file:"
0
puts
putcr

mov     ah
3Dh                 ;Open file command.
mov     al
0                   ;Open for reading.
push    ds
push    es                      ;Point ds:dx at name
pop     ds
mov     dx
di
int     21h                     ;Open the file
jnc     GoodOpen
print
byte    "DOS error #"
0
puti
print
byte    " opening file."
cr
lf
0
ExitPgm

GoodOpen:       pop     ds
mov     FileHandle
ax          ;Save file handle.


; Okay
read the data and display it:

ReadLoop:       mov     ah
3Fh                 ;Read file command
mov     bx
FileHandle
mov     cx
RecSize             ;Number of bytes.
mov     dx
offset month        ;Place to put data.
int     21h
jc      ReadError
test    ax
ax                  ;EOF?
je      Quit

mov     cx
year
mov     dl
day
mov     dh
month
dtoam
puts
free
print
byte    "
"
0

mov     ch
hour
mov     cl
minute
mov     dh
second
mov     dl
0
ttoam
puts
free
printf
byte    "
keystrokes = %d\n"
0
dword   KeyStrokes
jmp     ReadLoop

ReadError:      print
byte    "Error reading file"
cr
lf
0

Quit:           mov     bx
FileHandle
mov     ah
3Eh         ;Close file
int     21h
ExitPgm

Main            endp
cseg            ends

sseg            segment para stack 'stack'
stk             db      1024 dup ("stack ")
sseg            ends

zzzzzzseg       segment para public 'zzzzzz'
LastBytes       db      16 dup (?)
zzzzzzseg       ends
end     Main

Chapter Eighteen (Part 4)

Table of Content

Chapter Eighteen (Part 6)

Chapter Eighteen: Resident Programs (Part 5)
29 SEP 1996